1 Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age? A. 2 times B. 2 1 times 2 C. 2 3 times 4 D. 3 times Answer: Option A Explanation: Let Ronit's present age be x years. Then, father's present age =( x + 3 x ) years = 4 x years. (4 x + 8) = 5 ( x + 8) 2 8 x + 16 = 5 x + 40 3 x = 24 x = 8. Hence, required ratio = (4 x + 16) = 48 = 2. ( x + 16) 24 2. The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child? A. 4 years B. 8 years C. 10 years D. None of these Answer: Option A Explanation: Let the ages of children be x , ( x + 3), ( x + 6), ( x + 9) and ( x + 12) years. Then,...
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